(1/x^2)-4/x=0

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Solution for (1/x^2)-4/x=0 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

1/(x^2)-(4/x) = 0

1/(x^2)-4*x^-1 = 0

x^-2-4*x^-1 = 0

t_1 = x^-1

1*t_1^2-4*t_1^1 = 0

t_1^2-4*t_1 = 0

DELTA = (-4)^2-(0*1*4)

DELTA = 16

DELTA > 0

t_1 = (16^(1/2)+4)/(1*2) or t_1 = (4-16^(1/2))/(1*2)

t_1 = 4 or t_1 = 0

t_1 = 0

x^-1+0 = 0

x^-1 = 0

1*x^-1 = 0 // : 1

x^-1 = 0

x należy do O

t_1 = 4

x^-1-4 = 0

1*x^-1 = 4 // : 1

x^-1 = 4

-1 < 0

1/(x^1) = 4 // * x^1

1 = 4*x^1 // : 4

1/4 = x^1

x = 1/4

x = 1/4

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